当我有一个很大的结果时，Postgres 函数不起作用

debugcn 发表于 Dev

Eder Armando 戒指 Lora

我正在将信息从表 1(tmp_subtype) 复制到表 2(subtype_user)。我有一个带有 15 个寄存器的测试表 1。我将此函数运行到 postgres 中：

CREATE OR REPLACE FUNCTION VERIFY_AND_INSERT_SUPTYPE()
    RETURNS text AS $$
    DECLARE
       register_subtype RECORD;
       existe INT DEFAULT 0;
       MESSAGE_EXCEPTION TEXT;
       cursor_subtype CURSOR
       FOR
          SELECT tsd.subtype,tsd.type_id_client,tsd.id_client,tsd.email
          FROM tmp_subtype tsd;
    BEGIN

      OPEN cursor_subtype;
      LOOP
         FETCH cursor_subtype INTO register_subtype;
         EXIT WHEN NOT FOUND;

         SELECT COUNT(*) INTO existe FROM (
            SELECT sdu.id_client FROM subtype_user sdu
            WHERE sdu.id_client = register_subtype.id_client AND sdu.type_id_client = register_subtype.type_id_client
            LIMIT 1
         ) SUB0;

         IF existe = 0 THEN
            INSERT INTO subtype_user(subtype,type_id_client,id_client,email)
            VALUES (register_subtype.subtype,register_subtype.type_id_client,register_subtype.id_client,register_subtype.email);
         ELSE
            UPDATE subtype_user sdu2 SET subtype=register_subtype.subtype,email=register_subtype.email
            WHERE sdu2.id_client = register_subtype.id_client AND sdu2.type_id_client = register_subtype.type_id_client;
         END IF;
      END LOOP;
      CLOSE cursor_subtype;

      RETURN 'OK';

      EXCEPTION WHEN OTHERS THEN
            GET STACKED DIAGNOSTICS MESSAGE_EXCEPTION = MESSAGE_TEXT;
            RETURN MESSAGE_EXCEPTION;
    END; $$
    LANGUAGE plpgsql;

它有效，但是当我使用真实的表 1 运行此函数时，它不起作用。函数完成但什么也没发生。真正的表 1 有 100 万个寄存器。

a_horse_with_no_name

带有嵌入式计数的逐行处理是处理缓慢和低效的方法。此外，如果该函数是从并发事务中调用的，则您的存在检查将不起作用。据我所知，您可以使用单个 INSERT 语句替换整个循环和游标：

CREATE OR REPLACE FUNCTION VERIFY_AND_INSERT_SUPTYPE()
    RETURNS text 
AS $$
DECLARE
  MESSAGE_EXCEPTION TEXT;
BEGIN

  INSERT INTO subtype_user(subtype, type_id_client, id_client, email)
  SELECT tsd.subtype, tsd.type_id_client, tsd.id_client, tsd.email
  FROM tmp_subtype tsd
  ON conflict (id_client, type_id_client) DO UPDATE 
    SET  subtype = excluded.register_subtype,
         email = excluded.email;

  RETURN 'OK';

  EXCEPTION WHEN OTHERS THEN
        GET STACKED DIAGNOSTICS MESSAGE_EXCEPTION = MESSAGE_TEXT;
        RETURN MESSAGE_EXCEPTION;
END; $$
LANGUAGE plpgsql;

我可能不会在开始时添加异常处理程序，以便调用者看到完整的异常。

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