I'm trying to implement a piece of code on javascript to analyse word/frequency on a given string. My objective is to return a array as the following:
[{text: firstword, size:3 },{text:secondword , size:5 },{text: nword, size: 1},...]
I implemented the following code but I'm running out of memory, so I don't really know if its ok or not.
function wordFrequency(txt){
var wordArray = txt.split(/[ .?!,*'"]/);
var newArray = [];
$.each(wordArray, function (ix, word) {
if (newArray.length >= 1){
newArray.some(function (w){
if (w.text === word){
w.size++;
} else {
newArray.push({text: word, size: 1});
}
});
} else {
newArray.push({text: word, size: 1});
}
});
return newArray;
}
Array.prototype.some expects the given callback to return true or false and returns true as soon as your callback returns true for a given element, otherwise it returns false.
So some iterates over all elements, with your given callback, and your callback checks if the given element text equals the search word and if not adds a new object. Introducing a new element the some function can iterate over.
So to make this clear, for every word thats in the newArray before the word you're searching, you're adding a new object containing your word.
Suppose your newArray looks like this:
[{word:"test"},{word:"another"},{word:"one"},{word:"more"}]
after calling your function for the word even it looks like this:
[{word:"test"},{word:"another"},{word:"one"},{word:"more"},{word:"even"},{word:"even"},{word:"even"},{word:"even"}]
Using Array.prototype.filter would be the better approach here, finding you the matching element, note that I also replaced $.each with Array.prototype.forEach:
function wordFrequency(txt){
var wordArray = txt.split(/[ .?!,*'"]/);
var newArray = [], wordObj;
wordArray.forEach(function (word) {
wordObj = newArray.filter(function (w){
return w.text == word;
});
if (wordObj.length) {
wordObj[0].size += 1;
} else {
newArray.push({text: word, size: 1});
}
});
return newArray;
}
document.write(JSON.stringify(wordFrequency("count everything, count all the words, count all the words!").sort(function(a,b){return a.size<b.size})).split("},").join("}<br/>"));이 기사는 인터넷에서 수집됩니다. 재 인쇄 할 때 출처를 알려주십시오.
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