I have a 2D array created dynamically.
int **abc = new int*[rows];
for (uint32_t i = 0; i < rows; i++)
{
abc[i] = new int[cols];
}
I want to fill the array with some value (say 1). I can loop over each item and do it.
But is there a simpler way. I am trying to use memset and std::fill_n as mentioned in this post.
std::fill_n(abc, rows * cols, 1);
memset(abc, 1, rows * cols * sizeof(int));
Using memset crashes my program. Using fill_n gives a compile error.
invalid conversion from 'int' to 'int*' [-fpermissive]
What am I doing wrong here ?
You could just use vector:
std::vector<std::vector<int>> abc(rows, std::vector<int>(cols, 1));
You cannot use std::fill_n or memset on abc directly, it simply will not work. You can only use either on the sub-arrays:
int **abc = new int*[rows];
for (uint32_t i = 0; i < rows; i++)
{
abc[i] = new int[cols];
std::fill_n(abc[i], cols, 1);
}
Or make the whole thing single-dimensional:
int *abc = new int[rows * cols];
std::fill_n(abc, rows*cols, 1);
Or I guess you could use std::generate_n in combination with std::fill_n, but this just seems confusing:
int **abc = new int*[rows];
std::generate_n(abc, rows, [cols]{
int* row = new int[cols];
std::fill_n(row, cols, 1);
return row;
});
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