Is this Python code equivalent of Java code?

debugcn Published at Dev

Helquin

I'm fairly new to Python so please bear with me.

This is the Java code:

public static int countDeafRats(final String town) {
    String t = town.replaceAll(" ","");
    int count = 0;
    for (int i = 0 ; i < t.length() ; i+=2) 
        if (t.charAt(i) == 'O') count++;
    return count;
}

This is my attempt to translate it to Python:

def count_deaf_rats(town):
    count = 0
    increment = 0
    newTown = town.replace(" ", "")
    while increment <= len(newTown):
        if newTown[increment]=='O':
            count +=1
            increment +=2
    return count

I didn't use for loop in Python since I don't how to increment by 2, so as the title says, would this be an acceptable translation?

Edit, sample input: ~O~O~O~OP~O~OO~

Ajax1234

It appears that you are trying to find the number of zeroes in the string that occur at indices incremented by 2. You can use regex and list comprehensions in Python:

import re

new_town = re.sub("\s+", '', town)

count = sum(i == "0" for i in new_town[::2])

Collected from the Internet

Please contact [email protected] to delete if infringement.

edited at2021-07-31

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