I have a survey form. After submitting the form, I'd like to handle saving the data then redirect to a "sucess" view. I'm using the following code right now, but it just stays on the current url, while I'd like to go to /success. How can I do this?
@app.route('/surveytest', methods=['GET', 'POST'])
def surveytest():
if request.method == 'GET':
return render_template('test.html', title='Survey Test', year=datetime.now().year, message='This is the survey page.')
elif request.method == 'POST':
name = request.form['name']
address = request.form['address']
phone = request.form['phone']
email = request.form['email']
company = request.form['company']
return render_template('success.html', name=name, address=address, phone = phone, email = email, company = company)
You have the right goal: it's good to redirect after handling form data. Rather than returning render_template again, use redirect instead.
from flask import redirect, url_for, survey_id
@app.route('/success/<int:result_id>')
def success(result_id):
# replace this with a query from whatever database you're using
result = get_result_from_database(result_id)
# access the result in the tempalte, for example {{ result.name }}
return render_template('success.html', result=result)
@app.route('/survey', methods=["GET", "POST"])
def survey():
if request.method == 'POST':
# replace this with an insert into whatever database you're using
result = store_result_in_database(request.args)
return redirect(url_for('success', result_id=result.id))
# don't need to test request.method == 'GET'
return render_template('survey.html')
The redirect will be handled by the user's browser, and the new page at the new url will be loaded, rather than rendering a different template at the same url.
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