#include<stdio.h>
#include<math.h>
int main()
{
int rem, num, i, sum;
sum=0;
num=28;
for(i=1;i<num;i++)
{
if(num%i==0)
{
rem=num%i;
sum=sum+rem;
}
}
if(sum==num)
{
printf("perfect number");
}
else
printf("not perfect");
}
why are you doing this, you need to get the total sum of all the proper divisors (proper divisor of a natural number is the divisor that is strictly less than the number) of num, but what you are doing is adding rem = num%i, which is basically always 0 as num is divisible by i what you checked in your if, so what you are doing is not making any sense
if(num%i==0)
{
rem=num%i; // here `rem` is always `0` as `num%i == 0`
sum=sum+rem;
}
rather your logic should be like below, as the divisor is i so you should add all the divisors (representing by the i when num is divisible by i) in your sum
if(num%i==0)
{
sum = sum + i;
}
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