我目前正在使用此代码制作XML文件,在该代码中,我创建了一个对象,每次调用该方法时该对象都会写入XML文件:
public static void TileMapCapabilities(string title, TilePicker picker)
{
var dbInfo = picker.GetCapabilitiesInfo();
TileMapObject tmo = new TileMapObject()
{
Title = title,
Abstract = "",
KeywordList = new KeywordList() {FirstLayer = ""},
SRS = "OSGEO:41001",
Profile = "local",
Format = "image/png",
BoundingBox = dbInfo.eBoundingBox,
MapSize = dbInfo.mapSize,
CellSize = dbInfo.cellSize,
MaxLevel = dbInfo.level,
Location = dbInfo.location // Not sure if this should be here. Could be practical in scenarios where the tile server is hosted locally.
};}
它工作正常,可能看起来像这样:
<?xml version="1.0" encoding="utf-8"?>
<TileMapServicesObject xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<TileMapService>
<Title>EivaTMS</Title>
<Abstract>Something clever about this service</Abstract>
<TileMaps>
<TileMap>
<Title>kraken.db</Title>
<href>10.10.100.200/kraken.db?request=getcapabilities</href>
<Profile>global-mercator</Profile>
<SRS>OSGEO:41001</SRS>
</TileMap>
</TileMaps>
</TileMapService>
</TileMapServicesObject>
现在,我要做的是创建一个XML文件,该文件描述了上面提到的那一层之上的层。换句话说,我想要一个XML文件,并对上面的每个XML文件进行简短描述。
我已经设法完成了一些工作,如果我对值进行硬编码,它将看起来像这样:
public static void TileMapServicesCapabilities(int listBoxCount)
{
TileMapServicesObject tmso = new TileMapServicesObject()
{
TileMapService = new TileMapService()
{
Title = "EivaTMS",
Abstract = "Something clever about this service",
TileMaps = new List<TileMap>
{
new TileMap { Title = "title1", href = "http://title1/?request=getcapabilities", Profile = "global-mercator", SRS = "OSGEO:41001"},
new TileMap { Title = "title2", href = "http://title2/?request=getcapabilities", Profile = "global-mercator", SRS = "OSGEO:41001"},
new TileMap { Title = "title3", href = "http://title3/?request=getcapabilities", Profile = "global-mercator", SRS = "OSGEO:41001"}
}
}
};}
产生以下输出:
<?xml version="1.0" encoding="utf-8"?>
<TileMapServicesObject xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<TileMapService>
<Title>EivaTMS</Title>
<Abstract>Something clever about this service</Abstract>
<TileMaps>
<TileMap>
<Title>title1</Title>
<href>http://title1/?request=getcapabilities</href>
<Profile>global-mercator</Profile>
<SRS>OSGEO:41001</SRS>
</TileMap>
<TileMap>
<Title>title2</Title>
<href>http://title2/?request=getcapabilities</href>
<Profile>global-mercator</Profile>
<SRS>OSGEO:41001</SRS>
</TileMap>
<TileMap>
<Title>title3</Title>
<href>http://title3/?request=getcapabilities</href>
<Profile>global-mercator</Profile>
<SRS>OSGEO:41001</SRS>
</TileMap>
</TileMaps>
</TileMapService>
</TileMapServicesObject>
现在,我要做的是动态创建和添加元素。这意味着对于第一种方法创建的每个XML文件TileMapCapabilities
,我都想创建一个对象并将其添加到中TileMapServicesObject
。可能还值得一提的是,这些类的外观包含正在创建的对象中的信息:
public class TileMapServicesObject
{
public TileMapService TileMapService { get; set; }
}
public class TileMapService
{
public string Title { get; set; }
public string Abstract { get; set; }
public List<TileMap> TileMaps { get; set; }
}
public class TileMap
{
public string Title { get; set; }
public string href { get; set; }
public string Profile { get; set; }
public string SRS { get; set; }
}
我一直在尝试foreach循环,为要添加到服务中的每个TileMap创建一个TileMap对象,但这只是为每次迭代创建了一个新的TileMapServicesObject,而不是包含所有对象的单个文件。
关于如何解决此问题的任何提示?如果我的要求在目前的形式上过于含糊,请告诉我。
编辑:原来只是盯着它足够长时间来修复它!
这是更新的代码:
public static void TileMapServicesCapabilities()
{
TileMapServicesObject tmso = new TileMapServicesObject();
List<string> pathList = new List<string>();
pathList = Directory.GetFiles(path + @"Tilemaps\").ToList();
List<TileMap> tmList = new List<TileMap>();
TileMap tm = new TileMap();
string title = "";
string profile = "";
string srs = "";
foreach (var p in pathList)
{
var xRead = XDocument.Load(p);
var xd = (from el in xRead.Descendants("TileMapObject")
select new
{
Title = el.Element("Title").Value,
Profile = el.Element("Profile").Value,
SRS = el.Element("SRS").Value
}).SingleOrDefault();
title = xd.Title;
profile = xd.Profile;
srs = xd.SRS;
tm = new TileMap()
{
Title = title,
Profile = profile,
SRS = srs,
href = "http://10.10.100.200/" + title + "?request=getcapabilities"
};
tmList.Add(tm);
}
tmso = new TileMapServicesObject()
{
TileMapService = new TileMapService()
{
Title = "EivaTMS",
Abstract = "Something clever about this service",
TileMaps = tmList
}
};
这给了我这个漂亮的XML文件:
<?xml version="1.0" encoding="utf-8"?>
<TileMapServicesObject xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<TileMapService>
<Title>EivaTMS</Title>
<Abstract>Something clever about this service</Abstract>
<TileMaps>
<TileMap>
<Title>title1</Title>
<href>http://title1?request=getcapabilities</href>
<Profile>local</Profile>
<SRS>OSGEO:41001</SRS>
</TileMap>
<TileMap>
<Title>title2</Title>
<href>http://title2?request=getcapabilities</href>
<Profile>local</Profile>
<SRS>OSGEO:41001</SRS>
</TileMap>
<TileMap>
<Title>title3</Title>
<href>http://title3?request=getcapabilities</href>
<Profile>local</Profile>
<SRS>OSGEO:41001</SRS>
</TileMap>
<TileMap>
<Title>title4</Title>
<href>http://title4?request=getcapabilities</href>
<Profile>local</Profile>
<SRS>OSGEO:41001</SRS>
</TileMap>
</TileMaps>
</TileMapService>
</TileMapServicesObject>
好吧,经过数小时的盯着它,我设法解决了这个问题!
事实证明,我可以仅创建一个foreach(),在其中迭代要读取的所有文件,创建一个TileMap对象,并将其添加到List中,然后在foreach()之后写入XML。我已经用新代码更新了OP。
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