现在我正在尝试将结果附加到来自mysql查询的php中的变量,这是使用的代码:
<?php
$con=mysqli_connect("localhost","root","","ezsnip");
// Check connection
if (mysqli_connect_errno()) {
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$result = mysql_query("SELECT Snip FROM snips WHERE ID='1'");
$row = mysql_fetch_array($result);
$snip = $row['Snip'];
$snip = str_replace('<?php', '<?php', $snip);
$snip = str_replace('?>', '?>', $snip);
?>
<div id="editor"><?php echo $snip; ?></div>
当我运行代码时,它返回:mysql_fetch_array()期望参数1为资源,在170行的C:\ xampp \ htdocs \ home.php中给出布尔值
170行是:
$row = mysql_fetch_array($result);
mysql_query
创建mysqli
资源后要做的事
<?php
$con=mysqli_connect("localhost","root","","ezsnip");
// Check connection
if (mysqli_connect_errno()) {
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$result = mysqli_query($con,"SELECT Snip FROM snips WHERE ID='1'");
$row = mysqli_fetch_array($result);
$snip = $row['Snip'];
$snip = str_replace('<?php', '<?php', $snip);
$snip = str_replace('?>', '?>', $snip);
?>
<div id="editor"><?php echo $snip; ?></div>
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