根据php中的另一个数组值重新排列数组值

Raj 发表于 Dev

拉吉

我有2个数组（一个数组和一个多维数组）。

单数组“ A”看起来像

[questionid] => Array
        (
            [0] => 12
            [1] => 13
            [2] => 55
            [3] => 15
            [4] => 16
        )

多维数组“ B”看起来像

Array
(
    [0] => Array
        (
            [quid] => 12
            [answer] => AAA
        )

    [1] => Array
        (
            [quid] => 13
            [answer] => neighbour
        )

    [2] => Array
        (
            [quid] => 15
            [answer] =>
        )

    [3] => Array
        (
            [quid] => 16
            [answer] =>
        )

     [4] => Array
        (
            [quid] => 55
            [answer] =>
        )
)

现在，我要根据数组A中的值重新排列数组B（quid）的值。因此，在数组B中，quid last element（55）的值位于末尾，而在数组A中，它位于第3位。

我希望数组B看起来像这样

Array
(
    [0] => Array
        (
            [quid] => 12
            [answer] => AAA
        )

    [1] => Array
        (
            [quid] => 13
            [answer] => neighbour
        )

    [2] => Array
        (
            [quid] => 55
            [answer] =>
        )

    [3] => Array
        (
            [quid] => 15
            [answer] =>
        )

     [4] => Array
        (
            [quid] => 16
            [answer] =>
        )
)

多维数组的代码是

$ansid = array
(
     array
        (
            "quid" => 12,
            "answer" => "AAA"
        ),

     array
        (
            "quid" => 13,
            "answer" => "neighbour"
        ),

     array
        (
            "quid" => 15,
            "answer" =>""
        ),
     array
        (
            "quid" => 16,
            "answer" =>""
        ),

     array
        (
            "quid" => 55,
            "answer" =>""
        )
);

欧根·里克（Eugen Rieck）

不使用array_walk()mor作为示范，您可以

$newB=array()
foreach ($arrayB as $b) $newB[$b['quid']]=$b;
$newA=array()
foreach ($arrayA as $k=>$v) $newA[$k]=$newB[$v]
//$newA has the required structure

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