我在终端中有一个正在工作的GStreamer-1.0管道,我试图在Mac / Xcode上使用GStreamer 1.0在代码中复制它。
我的发送管道:
gst-launch-1.0 videotestsrc ! videoconvert ! x264enc ! rtph264pay config-interval=1 ! udpsink host=127.0.0.1 port=5000
我的接收管道:
gst-launch-1.0 -vvv udpsrc port=5000 caps="application/x-rtp" ! rtph264depay ! avdec_h264 ! videoconvert ! xvimagesink
也可以在VLC中使用以下SDP文件进行播放:
v=0
m=video 5000 RTP/AVP 96
c=IN IP4 127.0.0.1
a=rtpmap:96 H264/90000
我创建了以下代码来复制上述代码,但问题是在运行此代码时接收管道未显示任何内容。该代码确实根据Xcode调试控制台将数据包发送到网络。
gint
main (gint argc,
gchar *argv[])
{
GstElement *pipeline, *videosrc, *conv,*enc, *pay, *udp;
// init GStreamer
gst_init (&argc, &argv);
loop = g_main_loop_new (NULL, FALSE);
// setup pipeline
pipeline = gst_pipeline_new ("pipeline");
videosrc = gst_element_factory_make ("videotestsrc", "source");
conv = gst_element_factory_make ("videoconvert", "conv");
enc = gst_element_factory_make("x264enc", "enc");
pay = gst_element_factory_make("rtph264pay", "pay");
g_object_set(G_OBJECT(pay), "config-interval", 1, NULL);
udp = gst_element_factory_make("udpsink", "udp");
g_object_set(G_OBJECT(udp), "host", "127.0.0.1", NULL);
g_object_set(G_OBJECT(udp), "port", "5000", NULL);
gst_bin_add_many (GST_BIN (pipeline), videosrc, conv, enc, pay, udp, NULL);
if (gst_element_link_many (videosrc, conv, enc, pay, udp, NULL) != TRUE)
{
return -1;
}
// play
gst_element_set_state (pipeline, GST_STATE_PLAYING);
g_main_loop_run (loop);
// clean up
gst_element_set_state (pipeline, GST_STATE_NULL);
gst_object_unref (GST_OBJECT (pipeline));
g_main_loop_unref (loop);
return 0;
}
问题是端口参数应该是一个整数,所以我不得不更改
g_object_set(G_OBJECT(udp), "port", "5000", NULL);
至
g_object_set(G_OBJECT(udp), "port", 5000, NULL);
有时很容易错过自己的简单错误。
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我来说两句