如何获得鼠标点击

您已经可以pygame.mouse.get_pressed()使用它来检查单击了哪个按钮。

    option = 0

    if mouse_pressed[0]: # check if left button was clicked
        for i, but in enumerate(buttons, 1): # get button and its number
            if but.collidepoint(mouse_cursor): # check collision
                option = i # remember button number
                break      # no need to check other buttons

但是使用pygame.mouse.get_pressed()会产生一个问题-True按住鼠标按钮时，它会一直返回（因此每秒似乎有多次点击），因此，如果您更改屏幕上的按钮，并且新按钮将位于同一位置，则它将自动单击新按钮按钮。更好地使用event.type == pygame.MOUSEBUTTONDOWN它只创建一键。

while True:

    option = 0

    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            exit()
        if event.type == pygame.MOUSEBUTTONDOWN:
            for i, but in enumerate(buttons, 1):
                if but.collidepoint(event.pos):
                    option = i
                    break # no need to check other buttons

    if option == 1:
        print ("YO I GOT CLICKED")
    elif option == 2:
        print ("CLICKED MY DUDE")
    elif option == 3:
        quit()

    pygame.display.update()

顺便说一句：

您可以保留带有回调的按钮（函数名称不带()）

    buttons = [
        (play_button, play_function),
        (controls_button, control_function),
        (quit_button, quit_function),
    ]

然后您可以直接调用函数/回调（使用()），而无需option

            if event.type == pygame.MOUSEBUTTONDOWN:
                for rect, callback in buttons:
                    if rect.collidepoint(event.pos):
                        callback() # execute function
                        break # no need to check other buttons

完整的工作代码

import pygame

# --- constants --- (UPPER_CASE_NAMES)

SCREEN_WIDTH = 1280
SCREEN_HEIGHT = 950

WHITE = (255, 255, 255)

# --- functions --- (lower_case_names)

def play_function():
    print("YO I GOT CLICKED")

def controls_function():
    print("CLICKED MY DUDE")

def quit_function():
    pygame.quit()
    quit()

def menu(screen):

    # - init -

    title_font = pygame.font.SysFont("monospace", 64)
    button_font = pygame.font.SysFont("monospace", 30)

    # - objects -

    play_button = pygame.Rect(250,600,200,100)
    quit_button = pygame.Rect(850,600,200,100)
    controls_button = pygame.Rect(550,600,200,100)

    buttons = [
        (play_button, play_function),
        (controls_button, controls_function),
        (quit_button, quit_function),
    ]

    # - draws -

    screen.fill(WHITE)

    title = title_font.render("Fightastic!", 1, (0,0,0))
    screen.blit(title, (450,300))


    pygame.draw.rect(screen, (0,255,0), play_button)
    play_text = button_font.render("START",1,(0,0,0))
    screen.blit(play_text, (310,635))

    pygame.draw.rect(screen, (255,0,0), quit_button)
    quit_text = button_font.render("QUIT",1,(0,0,0))
    screen.blit(quit_text, (910,635))

    pygame.draw.rect(screen, (255,229,0), controls_button)
    controls_text = button_font.render("CONTROLS",1,(0,0,0))
    screen.blit(controls_text, (580,635))

    pygame.display.update()

    # - mainloop -

    clock = pygame.time.Clock()

    while True:

        for event in pygame.event.get():
            if event.type == pygame.QUIT:
                exit()
            if event.type == pygame.MOUSEBUTTONDOWN:
                for rect, callback in buttons:
                    if rect.collidepoint(event.pos):
                        callback() # execute function
                        break # no need to check other buttons

        clock.tick(5) # 5 FPS - to slow down game and use less CPU

# --- main ---

pygame.init()
screen = pygame.display.set_mode((SCREEN_WIDTH, SCREEN_HEIGHT))

menu(screen)