如何根据var2和var1更改var3的值？我想在var2 = 0时将var3的值加倍。例如对于var1 = A，当var2 = 0时我希望var3 = 2 * 10000。我尝试了以下代码，这是错误的。有人可以帮忙吗？谢谢！
dat2 <- data_frame(
var1 = factor(rep(dat1$var1, each=2)),
var2 = factor(rep(0:1, 8) ),
var3 = rep(dat1$var3*ifelse(dat1$var2==0, 2, 1), each =1)
)
Var1 var2 var3
1 A 0 10000
2 A 1 10000
3 B 0 15000
4 B 1 15000
5 C 0 18000
6 C 1 18000
7 D 0 12500
8 D 1 12500
9 E 0 19500
10 E 1 19500
11 F 0 15500
12 F 1 15500
13 G 0 20500
14 G 1 20500
15 H 0 10500
16 H 1 10500
不确定我是否完全了解分配规则。看看哪一套适合。
# the sample data
df = structure(list(Var1 = structure(c(1L, 1L, 2L, 2L, 3L, 3L, 4L,
4L, 5L, 5L, 6L, 6L, 7L, 7L, 8L, 8L), .Label = c("A", "B", "C",
"D", "E", "F", "G", "H"), class = "factor"), var2 = c(0L, 1L,
0L, 1L, 0L, 1L, 0L, 1L, 0L, 1L, 0L, 1L, 0L, 1L, 0L, 1L), var3 = c(10000L,
10000L, 15000L, 15000L, 18000L, 18000L, 12500L, 12500L, 19500L,
19500L, 15500L, 15500L, 20500L, 20500L, 10500L, 10500L)), .Names = c("Var1",
"var2", "var3"), class = "data.frame", row.names = c("1", "2",
"3", "4", "5", "6", "7", "8", "9", "10", "11", "12", "13", "14",
"15", "16"))
# assumption 1 : only double var3 when var2 == 0
df$var3_new <- ifelse(df$var2 == 0, df$var3*2, df$var3)
# assumption 2 : only double var3 when Var1 == "A" & var2 == 0
df$var3_new <- ifelse(df$Var1 == "A" & df$var2 == 0,
df$var3*2, df$var3)
# Here I assign the updated values to var3_new column so that you could
# compare. You could change var3_new to var3 so that var3 will be
# re-written with new values according to your formula. Happy
# exploration.
# As to ifelse, basically the logic is:
# ifelse(condition_1,
# assign a value if condition_1 is satisfied,
# assign other values otherwise)
最后，建议ifelse在此站点中搜索。应该有足够的例子。
本文收集自互联网，转载请注明来源。
如有侵权，请联系[email protected] 删除。
我来说两句