我已使用以下代码从Firestore存储中检索了数据：
class User {
bool isActive;
String databaseID;
String email;
User() {
this.isActive = '';
this.databaseID = '';
this.email = '';
}
toJson() {
return {
'isActive': this.isActive,
"databaseID": this.databaseID,
"email": this.email,
"
};
}
fromJson(Map<String, dynamic> json) {
this.isActive = json['isActive'];
this.databaseID = json["databaseID"];
this.email = json["email"];
});
}
}
数据由databaseID，电子邮件地址和isActive方法组成，该方法确定用户是否处于活动状态。isActive是数据库中具有true和false方法的布尔值。现在，我想编写一个查询，如果isActive为false，则应打印“ User is not active”，否则应打印“ User is active”。我已经编写了这段代码，但是它给出了错误
try {
// get isActive if available
bool isActive = this.isActive;
if (isActive == false) {
return false;
}
else {
return true;
}
} catch (error) {
print(error);
return null;
}
}
将类更改为以下内容：
class User {
bool isActive;
String databaseID;
String email;
User() {
this.isActive = true;
this.databaseID = '';
this.email = '';
}
toJson() {
return {
'isActive': this.isActive,
"databaseID": this.databaseID,
"email": this.email,
};
}
fromJson(Map<String, dynamic> json) {
this.isActive = json['isActive'];
this.databaseID = json["databaseID"];
this.email = json["email"];
}
}
isActive是类型的，bool因此您应该分配true或false不分配string。然后要分配isActive给变量，您必须创建class的实例User：
User user = new User();
user.isActive = false;
bool isActive = user.isActive;
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